Integrand size = 30, antiderivative size = 258 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=-\frac {c}{12 a^3 x^{12}}+\frac {3 b c-a d}{9 a^4 x^9}-\frac {6 b^2 c-3 a b d+a^2 e}{6 a^5 x^6}+\frac {10 b^3 c-6 a b^2 d+3 a^2 b e-a^3 f}{3 a^6 x^3}+\frac {b \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right )}{6 a^5 \left (a+b x^3\right )^2}+\frac {b \left (5 b^3 c-4 a b^2 d+3 a^2 b e-2 a^3 f\right )}{3 a^6 \left (a+b x^3\right )}+\frac {b \left (15 b^3 c-10 a b^2 d+6 a^2 b e-3 a^3 f\right ) \log (x)}{a^7}-\frac {b \left (15 b^3 c-10 a b^2 d+6 a^2 b e-3 a^3 f\right ) \log \left (a+b x^3\right )}{3 a^7} \]
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Time = 0.20 (sec) , antiderivative size = 258, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.067, Rules used = {1835, 1634} \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {3 b c-a d}{9 a^4 x^9}-\frac {c}{12 a^3 x^{12}}-\frac {a^2 e-3 a b d+6 b^2 c}{6 a^5 x^6}-\frac {b \log \left (a+b x^3\right ) \left (-3 a^3 f+6 a^2 b e-10 a b^2 d+15 b^3 c\right )}{3 a^7}+\frac {b \log (x) \left (-3 a^3 f+6 a^2 b e-10 a b^2 d+15 b^3 c\right )}{a^7}+\frac {b \left (-2 a^3 f+3 a^2 b e-4 a b^2 d+5 b^3 c\right )}{3 a^6 \left (a+b x^3\right )}+\frac {a^3 (-f)+3 a^2 b e-6 a b^2 d+10 b^3 c}{3 a^6 x^3}+\frac {b \left (a^3 (-f)+a^2 b e-a b^2 d+b^3 c\right )}{6 a^5 \left (a+b x^3\right )^2} \]
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Rule 1634
Rule 1835
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {c+d x+e x^2+f x^3}{x^5 (a+b x)^3} \, dx,x,x^3\right ) \\ & = \frac {1}{3} \text {Subst}\left (\int \left (\frac {c}{a^3 x^5}+\frac {-3 b c+a d}{a^4 x^4}+\frac {6 b^2 c-3 a b d+a^2 e}{a^5 x^3}+\frac {-10 b^3 c+6 a b^2 d-3 a^2 b e+a^3 f}{a^6 x^2}-\frac {b \left (-15 b^3 c+10 a b^2 d-6 a^2 b e+3 a^3 f\right )}{a^7 x}+\frac {b^2 \left (-b^3 c+a b^2 d-a^2 b e+a^3 f\right )}{a^5 (a+b x)^3}+\frac {b^2 \left (-5 b^3 c+4 a b^2 d-3 a^2 b e+2 a^3 f\right )}{a^6 (a+b x)^2}+\frac {b^2 \left (-15 b^3 c+10 a b^2 d-6 a^2 b e+3 a^3 f\right )}{a^7 (a+b x)}\right ) \, dx,x,x^3\right ) \\ & = -\frac {c}{12 a^3 x^{12}}+\frac {3 b c-a d}{9 a^4 x^9}-\frac {6 b^2 c-3 a b d+a^2 e}{6 a^5 x^6}+\frac {10 b^3 c-6 a b^2 d+3 a^2 b e-a^3 f}{3 a^6 x^3}+\frac {b \left (b^3 c-a b^2 d+a^2 b e-a^3 f\right )}{6 a^5 \left (a+b x^3\right )^2}+\frac {b \left (5 b^3 c-4 a b^2 d+3 a^2 b e-2 a^3 f\right )}{3 a^6 \left (a+b x^3\right )}+\frac {b \left (15 b^3 c-10 a b^2 d+6 a^2 b e-3 a^3 f\right ) \log (x)}{a^7}-\frac {b \left (15 b^3 c-10 a b^2 d+6 a^2 b e-3 a^3 f\right ) \log \left (a+b x^3\right )}{3 a^7} \\ \end{align*}
Time = 0.20 (sec) , antiderivative size = 238, normalized size of antiderivative = 0.92 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {-\frac {a \left (-180 b^5 c x^{15}+30 a b^4 x^{12} \left (-9 c+4 d x^3\right )-12 a^2 b^3 x^9 \left (5 c-15 d x^3+6 e x^6\right )-2 a^4 b x^3 \left (3 c+5 d x^3+12 e x^6-27 f x^9\right )+a^5 \left (3 c+4 d x^3+6 e x^6+12 f x^9\right )+a^3 b^2 x^6 \left (15 c+40 d x^3-108 e x^6+36 f x^9\right )\right )}{x^{12} \left (a+b x^3\right )^2}+36 b \left (15 b^3 c-10 a b^2 d+6 a^2 b e-3 a^3 f\right ) \log (x)+12 b \left (-15 b^3 c+10 a b^2 d-6 a^2 b e+3 a^3 f\right ) \log \left (a+b x^3\right )}{36 a^7} \]
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Time = 1.52 (sec) , antiderivative size = 253, normalized size of antiderivative = 0.98
method | result | size |
default | \(-\frac {c}{12 a^{3} x^{12}}-\frac {a d -3 b c}{9 a^{4} x^{9}}-\frac {a^{2} e -3 a b d +6 b^{2} c}{6 a^{5} x^{6}}-\frac {f \,a^{3}-3 a^{2} b e +6 a \,b^{2} d -10 b^{3} c}{3 a^{6} x^{3}}-\frac {b \left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) \ln \left (x \right )}{a^{7}}+\frac {b^{2} \left (\frac {\left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) \ln \left (b \,x^{3}+a \right )}{b}-\frac {a^{2} \left (f \,a^{3}-a^{2} b e +a \,b^{2} d -b^{3} c \right )}{2 b \left (b \,x^{3}+a \right )^{2}}-\frac {a \left (2 f \,a^{3}-3 a^{2} b e +4 a \,b^{2} d -5 b^{3} c \right )}{b \left (b \,x^{3}+a \right )}\right )}{3 a^{7}}\) | \(253\) |
norman | \(\frac {-\frac {c}{12 a}-\frac {\left (2 a d -3 b c \right ) x^{3}}{18 a^{2}}-\frac {\left (6 a^{2} e -10 a b d +15 b^{2} c \right ) x^{6}}{36 a^{3}}-\frac {\left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) x^{9}}{9 a^{4}}+\frac {\left (-3 a^{3} b^{3} f +6 a^{2} b^{4} e -10 a \,b^{5} d +15 b^{6} c \right ) x^{12}}{2 a^{5} b^{2}}+\frac {\left (-3 a^{3} b^{3} f +6 a^{2} b^{4} e -10 a \,b^{5} d +15 b^{6} c \right ) x^{15}}{3 a^{6} b}}{x^{12} \left (b \,x^{3}+a \right )^{2}}-\frac {b \left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) \ln \left (x \right )}{a^{7}}+\frac {b \left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) \ln \left (b \,x^{3}+a \right )}{3 a^{7}}\) | \(262\) |
risch | \(\frac {-\frac {c}{12 a}-\frac {\left (2 a d -3 b c \right ) x^{3}}{18 a^{2}}-\frac {\left (6 a^{2} e -10 a b d +15 b^{2} c \right ) x^{6}}{36 a^{3}}-\frac {\left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) x^{9}}{9 a^{4}}-\frac {b \left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) x^{12}}{2 a^{5}}-\frac {b^{2} \left (3 f \,a^{3}-6 a^{2} b e +10 a \,b^{2} d -15 b^{3} c \right ) x^{15}}{3 a^{6}}}{x^{12} \left (b \,x^{3}+a \right )^{2}}-\frac {3 b \ln \left (x \right ) f}{a^{4}}+\frac {6 b^{2} \ln \left (x \right ) e}{a^{5}}-\frac {10 b^{3} \ln \left (x \right ) d}{a^{6}}+\frac {15 b^{4} \ln \left (x \right ) c}{a^{7}}+\frac {b \ln \left (-b \,x^{3}-a \right ) f}{a^{4}}-\frac {2 b^{2} \ln \left (-b \,x^{3}-a \right ) e}{a^{5}}+\frac {10 b^{3} \ln \left (-b \,x^{3}-a \right ) d}{3 a^{6}}-\frac {5 b^{4} \ln \left (-b \,x^{3}-a \right ) c}{a^{7}}\) | \(293\) |
parallelrisch | \(-\frac {-60 x^{9} a^{3} b^{5} c +6 x^{6} a^{6} b^{2} e -10 x^{6} a^{5} b^{3} d +15 x^{6} a^{4} b^{4} c +4 x^{3} a^{6} b^{2} d -6 x^{3} a^{5} b^{3} c -540 \ln \left (x \right ) x^{18} b^{8} c +180 \ln \left (b \,x^{3}+a \right ) x^{18} b^{8} c +3 a^{6} b^{2} c +108 \ln \left (x \right ) x^{12} a^{5} b^{3} f -216 \ln \left (x \right ) x^{12} a^{4} b^{4} e +360 \ln \left (x \right ) x^{12} a^{3} b^{5} d -540 \ln \left (x \right ) x^{12} a^{2} b^{6} c -36 \ln \left (b \,x^{3}+a \right ) x^{12} a^{5} b^{3} f +72 \ln \left (b \,x^{3}+a \right ) x^{12} a^{4} b^{4} e -120 \ln \left (b \,x^{3}+a \right ) x^{12} a^{3} b^{5} d +180 \ln \left (b \,x^{3}+a \right ) x^{12} a^{2} b^{6} c +36 x^{15} a^{4} b^{4} f -72 x^{15} a^{3} b^{5} e +120 x^{15} a^{2} b^{6} d -180 x^{15} a \,b^{7} c +54 x^{12} a^{5} b^{3} f -108 x^{12} a^{4} b^{4} e +180 x^{12} a^{3} b^{5} d -270 x^{12} a^{2} b^{6} c +12 x^{9} a^{6} b^{2} f -24 x^{9} a^{5} b^{3} e +40 x^{9} a^{4} b^{4} d +108 \ln \left (x \right ) x^{18} a^{3} b^{5} f -216 \ln \left (x \right ) x^{18} a^{2} b^{6} e +360 \ln \left (x \right ) x^{18} a \,b^{7} d -36 \ln \left (b \,x^{3}+a \right ) x^{18} a^{3} b^{5} f +72 \ln \left (b \,x^{3}+a \right ) x^{18} a^{2} b^{6} e -120 \ln \left (b \,x^{3}+a \right ) x^{18} a \,b^{7} d +216 \ln \left (x \right ) x^{15} a^{4} b^{4} f -432 \ln \left (x \right ) x^{15} a^{3} b^{5} e +720 \ln \left (x \right ) x^{15} a^{2} b^{6} d -1080 \ln \left (x \right ) x^{15} a \,b^{7} c -72 \ln \left (b \,x^{3}+a \right ) x^{15} a^{4} b^{4} f +144 \ln \left (b \,x^{3}+a \right ) x^{15} a^{3} b^{5} e -240 \ln \left (b \,x^{3}+a \right ) x^{15} a^{2} b^{6} d +360 \ln \left (b \,x^{3}+a \right ) x^{15} a \,b^{7} c}{36 a^{7} b^{2} x^{12} \left (b \,x^{3}+a \right )^{2}}\) | \(627\) |
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Time = 0.31 (sec) , antiderivative size = 448, normalized size of antiderivative = 1.74 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {12 \, {\left (15 \, a b^{5} c - 10 \, a^{2} b^{4} d + 6 \, a^{3} b^{3} e - 3 \, a^{4} b^{2} f\right )} x^{15} + 18 \, {\left (15 \, a^{2} b^{4} c - 10 \, a^{3} b^{3} d + 6 \, a^{4} b^{2} e - 3 \, a^{5} b f\right )} x^{12} + 4 \, {\left (15 \, a^{3} b^{3} c - 10 \, a^{4} b^{2} d + 6 \, a^{5} b e - 3 \, a^{6} f\right )} x^{9} - 3 \, a^{6} c - {\left (15 \, a^{4} b^{2} c - 10 \, a^{5} b d + 6 \, a^{6} e\right )} x^{6} + 2 \, {\left (3 \, a^{5} b c - 2 \, a^{6} d\right )} x^{3} - 12 \, {\left ({\left (15 \, b^{6} c - 10 \, a b^{5} d + 6 \, a^{2} b^{4} e - 3 \, a^{3} b^{3} f\right )} x^{18} + 2 \, {\left (15 \, a b^{5} c - 10 \, a^{2} b^{4} d + 6 \, a^{3} b^{3} e - 3 \, a^{4} b^{2} f\right )} x^{15} + {\left (15 \, a^{2} b^{4} c - 10 \, a^{3} b^{3} d + 6 \, a^{4} b^{2} e - 3 \, a^{5} b f\right )} x^{12}\right )} \log \left (b x^{3} + a\right ) + 36 \, {\left ({\left (15 \, b^{6} c - 10 \, a b^{5} d + 6 \, a^{2} b^{4} e - 3 \, a^{3} b^{3} f\right )} x^{18} + 2 \, {\left (15 \, a b^{5} c - 10 \, a^{2} b^{4} d + 6 \, a^{3} b^{3} e - 3 \, a^{4} b^{2} f\right )} x^{15} + {\left (15 \, a^{2} b^{4} c - 10 \, a^{3} b^{3} d + 6 \, a^{4} b^{2} e - 3 \, a^{5} b f\right )} x^{12}\right )} \log \left (x\right )}{36 \, {\left (a^{7} b^{2} x^{18} + 2 \, a^{8} b x^{15} + a^{9} x^{12}\right )}} \]
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Timed out. \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\text {Timed out} \]
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Time = 0.21 (sec) , antiderivative size = 280, normalized size of antiderivative = 1.09 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {12 \, {\left (15 \, b^{5} c - 10 \, a b^{4} d + 6 \, a^{2} b^{3} e - 3 \, a^{3} b^{2} f\right )} x^{15} + 18 \, {\left (15 \, a b^{4} c - 10 \, a^{2} b^{3} d + 6 \, a^{3} b^{2} e - 3 \, a^{4} b f\right )} x^{12} + 4 \, {\left (15 \, a^{2} b^{3} c - 10 \, a^{3} b^{2} d + 6 \, a^{4} b e - 3 \, a^{5} f\right )} x^{9} - {\left (15 \, a^{3} b^{2} c - 10 \, a^{4} b d + 6 \, a^{5} e\right )} x^{6} - 3 \, a^{5} c + 2 \, {\left (3 \, a^{4} b c - 2 \, a^{5} d\right )} x^{3}}{36 \, {\left (a^{6} b^{2} x^{18} + 2 \, a^{7} b x^{15} + a^{8} x^{12}\right )}} - \frac {{\left (15 \, b^{4} c - 10 \, a b^{3} d + 6 \, a^{2} b^{2} e - 3 \, a^{3} b f\right )} \log \left (b x^{3} + a\right )}{3 \, a^{7}} + \frac {{\left (15 \, b^{4} c - 10 \, a b^{3} d + 6 \, a^{2} b^{2} e - 3 \, a^{3} b f\right )} \log \left (x^{3}\right )}{3 \, a^{7}} \]
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Time = 0.28 (sec) , antiderivative size = 372, normalized size of antiderivative = 1.44 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {{\left (15 \, b^{4} c - 10 \, a b^{3} d + 6 \, a^{2} b^{2} e - 3 \, a^{3} b f\right )} \log \left ({\left | x \right |}\right )}{a^{7}} - \frac {{\left (15 \, b^{5} c - 10 \, a b^{4} d + 6 \, a^{2} b^{3} e - 3 \, a^{3} b^{2} f\right )} \log \left ({\left | b x^{3} + a \right |}\right )}{3 \, a^{7} b} + \frac {45 \, b^{6} c x^{6} - 30 \, a b^{5} d x^{6} + 18 \, a^{2} b^{4} e x^{6} - 9 \, a^{3} b^{3} f x^{6} + 100 \, a b^{5} c x^{3} - 68 \, a^{2} b^{4} d x^{3} + 42 \, a^{3} b^{3} e x^{3} - 22 \, a^{4} b^{2} f x^{3} + 56 \, a^{2} b^{4} c - 39 \, a^{3} b^{3} d + 25 \, a^{4} b^{2} e - 14 \, a^{5} b f}{6 \, {\left (b x^{3} + a\right )}^{2} a^{7}} - \frac {375 \, b^{4} c x^{12} - 250 \, a b^{3} d x^{12} + 150 \, a^{2} b^{2} e x^{12} - 75 \, a^{3} b f x^{12} - 120 \, a b^{3} c x^{9} + 72 \, a^{2} b^{2} d x^{9} - 36 \, a^{3} b e x^{9} + 12 \, a^{4} f x^{9} + 36 \, a^{2} b^{2} c x^{6} - 18 \, a^{3} b d x^{6} + 6 \, a^{4} e x^{6} - 12 \, a^{3} b c x^{3} + 4 \, a^{4} d x^{3} + 3 \, a^{4} c}{36 \, a^{7} x^{12}} \]
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Time = 0.32 (sec) , antiderivative size = 265, normalized size of antiderivative = 1.03 \[ \int \frac {c+d x^3+e x^6+f x^9}{x^{13} \left (a+b x^3\right )^3} \, dx=\frac {\ln \left (x\right )\,\left (-3\,f\,a^3\,b+6\,e\,a^2\,b^2-10\,d\,a\,b^3+15\,c\,b^4\right )}{a^7}-\frac {\ln \left (b\,x^3+a\right )\,\left (-3\,f\,a^3\,b+6\,e\,a^2\,b^2-10\,d\,a\,b^3+15\,c\,b^4\right )}{3\,a^7}-\frac {\frac {c}{12\,a}-\frac {x^9\,\left (-3\,f\,a^3+6\,e\,a^2\,b-10\,d\,a\,b^2+15\,c\,b^3\right )}{9\,a^4}+\frac {x^3\,\left (2\,a\,d-3\,b\,c\right )}{18\,a^2}+\frac {x^6\,\left (6\,e\,a^2-10\,d\,a\,b+15\,c\,b^2\right )}{36\,a^3}-\frac {b\,x^{12}\,\left (-3\,f\,a^3+6\,e\,a^2\,b-10\,d\,a\,b^2+15\,c\,b^3\right )}{2\,a^5}-\frac {b^2\,x^{15}\,\left (-3\,f\,a^3+6\,e\,a^2\,b-10\,d\,a\,b^2+15\,c\,b^3\right )}{3\,a^6}}{a^2\,x^{12}+2\,a\,b\,x^{15}+b^2\,x^{18}} \]
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